Show Random image - Invalid argument error

Hi aquaman,

I think the error you were getting was because some of your variable names didn't match up.

Does this work for you?

<?php // Display random image from selected category in table "header_images_small"
list($header_images_smallRecords, $header_images_smallMetaData) = getRecords(array(
'tableName' => 'header_images_small',
'where' => "category ='{$blogRecord['static_image_random']}'", //Gets the category id chosen in "blog"
'orderBy' => 'RAND()',
'limit' => 1,
'allowSearch' => '0',
));
$header_images_smallRecord = $header_images_smallRecords[0]; // get first record
?>

<div class="feature">
<?php shuffle($header_images_smallRecord['image']) ?>
<?php foreach ($header_images_smallRecord['image'] as $upload): ?>
<?php if ($upload['isImage']): ?>
<img src="<?php echo $upload['urlPath'] ?>" width="<?php echo $upload['width'] ?>" height="<?php echo $upload['height'] ?>" alt="<?php echo $header_images_smallRecord['title'] ?>" />
<?php endif ?>
<?php break ?>
<?php endforeach ?>
</div>

I hope this helps. Please let me know if you have any questions.

Hi Chris, I'm getting these errors now, see http://staging.naia.com.fj/post.php?coral-3

Notice: Undefined offset: 0 in /home/naia/www/staging.naia.com.fj/post.php on line 81
Warning: shuffle() expects parameter 1 to be array, null given in /home/naia/www/staging.naia.com.fj/post.php on line 85
Warning: Invalid argument supplied for foreach() in /home/naia/www/staging.naia.com.fj/post.php on line 86

Have attached the full page below. Look for the section:
<?php elseif ($blogRecord['header_type'] == 'random'): ?>

A few notes:

The random images are being pulled from a table called:
header_images_small which has the following fields: title, image, category. The field "category" is setup to pull the values from a different table - see attached image of setup.

Many thanks for your help!!
Jan

Hi Chris, Thanks so much for persisting with this...

I have added that code and it spits out this:

Could not find a header_images_small record for category = '1'

I checked in phpmyadmin to be sure there are a bunch of images with category set to 1 (see attached)

Hi aquaman,

Ahh, I can see from your screenshot that your category field is a "multi-value" list field. To check if a value is in a multi-value list field, you'll need to use a LIKE test:

'where' => "category LIKE '%\t{$blogRecord['static_image_random']}\t%'", //Gets the category id chosen in "blog"

I hope this helps. Please let me know if you have any questions.

Fantastic, That worked!

Thanks so much for your outstanding help & support.

cheers
Jan