Show Random image - Invalid argument error

7 posts by 2 authors in: Forums > CMS Builder
Last Post: January 7, 2010   (RSS)

By theclicklab - January 2, 2010 - edited: January 2, 2010

Hi there,

I'm trying to show a random image from a separate table in a page but am getting the following error:

"Invalid argument supplied for foreach()

The images are in a table called "header_images_small" and I'm trying to select a subset of images based on a field "category" in "header_images_small"

Here's the code:

<?php else: ?>
<?php // Display random image from selected category in table "header_images_small"
list($header_images_smallRecords, $header_images_smallMetaData) = getRecords(array(
'tableName' => 'header_images_small',
'where' => "category ='{$blogRecord['static_image_random']}'", //Gets the category id chosen in "blog"
'allowSearch' => '0',
));
?>

<div class="feature">
<?php foreach ($header_images_smallRecord['image'] as $upload): //Throwing an error here "Invalid argument supplied for foreach()" ?>
<?php shuffle($record['image']) ?>
<?php if ($upload['isImage']): ?>
<img src="<?php echo $upload['urlPath'] ?>" width="<?php echo $upload['width'] ?>" height="<?php echo $upload['height'] ?>" alt="<?php echo $header_images_smallRecord['title'] ?>" />
<?php endif ?>
<?php break ?>
<?php endforeach ?>
</div>

Re: [aquaman] Show Random image - Invalid argument error

By Chris - January 5, 2010

Hi aquaman,

I think the error you were getting was because some of your variable names didn't match up.

Does this work for you?

<?php // Display random image from selected category in table "header_images_small"
list($header_images_smallRecords, $header_images_smallMetaData) = getRecords(array(
'tableName' => 'header_images_small',
'where' => "category ='{$blogRecord['static_image_random']}'", //Gets the category id chosen in "blog"
'orderBy' => 'RAND()',
'limit' => 1,
'allowSearch' => '0',
));
$header_images_smallRecord = $header_images_smallRecords[0]; // get first record
?>

<div class="feature">
<?php shuffle($header_images_smallRecord['image']) ?>
<?php foreach ($header_images_smallRecord['image'] as $upload): ?>
<?php if ($upload['isImage']): ?>
<img src="<?php echo $upload['urlPath'] ?>" width="<?php echo $upload['width'] ?>" height="<?php echo $upload['height'] ?>" alt="<?php echo $header_images_smallRecord['title'] ?>" />
<?php endif ?>
<?php break ?>
<?php endforeach ?>
</div>


I hope this helps. Please let me know if you have any questions.
All the best,
Chris

Re: [chris] Show Random image - Invalid argument error

By theclicklab - January 5, 2010

Hi Chris, I'm getting these errors now, see http://staging.naia.com.fj/post.php?coral-3

Notice: Undefined offset: 0 in /home/naia/www/staging.naia.com.fj/post.php on line 81
Warning: shuffle() expects parameter 1 to be array, null given in /home/naia/www/staging.naia.com.fj/post.php on line 85
Warning: Invalid argument supplied for foreach() in /home/naia/www/staging.naia.com.fj/post.php on line 86

Have attached the full page below. Look for the section:
<?php elseif ($blogRecord['header_type'] == 'random'): ?>

A few notes:

The random images are being pulled from a table called:
header_images_small which has the following fields: title, image, category. The field "category" is setup to pull the values from a different table - see attached image of setup.

Many thanks for your help!!
Jan

Re: [aquaman] Show Random image - Invalid argument error

By Chris - January 5, 2010

Hi aquaman,

Please change this:

$header_images_smallRecord = $header_images_smallRecords[0]; // get first record

to this:

$header_images_smallRecord = @$header_images_smallRecords[0]; // get first record
if (!$header_images_smallRecord) { print "Could not find a header_images_small record for category = '{$blogRecord['static_image_random']}'"; exit; }


Hopefully that will give us more information about the problem. Are you sure there are records for that category?

Please let me know what you discover.
All the best,
Chris

Re: [aquaman] Show Random image - Invalid argument error

By Chris - January 7, 2010

Hi aquaman,

Ahh, I can see from your screenshot that your category field is a "multi-value" list field. To check if a value is in a multi-value list field, you'll need to use a LIKE test:

'where' => "category LIKE '%\t{$blogRecord['static_image_random']}\t%'", //Gets the category id chosen in "blog"

I hope this helps. Please let me know if you have any questions.
All the best,
Chris

Re: [chris] Show Random image - Invalid argument error

By theclicklab - January 7, 2010

Fantastic, That worked!

Thanks so much for your outstanding help & support.

cheers
Jan