How can I get the nth upload for a record?

Hi Ron,

here's a recipe from my CMSB Cookbook http://www.thecmsbcookbook.com that adresses that question.

Hope it helps,

Jerry Kornbluth

DISPLAY A SPECIFIC IMAGE FROM A SPECIFIC RECORD


My client wanted to be able to display a specific image from a group of records and multi image uploads.

I couldn’t get this to work until Chris Waddell from Interactive Tools unlocked the secret.

He said:

If $affiliationsRecords is a list of all your records, then $affiliationsRecords[0] will give you the first record, $affiliationsRecords[1] will give you the second, etc. It's a little confusing that the counting starts at 0 instead of 1.

$affiliationsRecords[3]['logo'][2] will grab the fourth record ([3]), its list of images (['logo']), and select its third image ([2]).

Since $affiliationsRecords[1]['logo'] refers to the list of images. You need to use $affiliationsRecords[1]['logo'][0] if you want to refer to a specific image ([0] gives you the first one, etc.)

You’ll need to define a variable for the specific image. To call the 3rd image from the 4th record I used

_____ code ________________________________________________

<?php $myImage = $affiliationsRecords[3]['logo'][2]; ?>

__________________________________________________________

The code that you’d use in the body of your viewer page where you want the image to display would be:

_____ code ________________________________________________

<?php $myImage = $affiliationsRecords[3]['logo'][2]; ?>
<img src="<?php echo $myImage['thumbUrlPath'] ?>" width="<?php echo $myImage['thumbWidth'] ?>" height="<?php echo $myImage['thumbHeight'] ?>" alt="" />

__________________________________________________________

You can also define other variables, like this one for the link to a detail page relating to the same record:

_____ code ________________________________________________

<?php @$mylink = $affiliationsRecords[4]['_link']; ?>

__________________________________________________________

Then the code including a linked image might look like this:

_____ code ________________________________________________

<?php @$myImage = $affiliationsRecords[3]['logo'][2]; ?>
<?php @$mylink = $affiliationsRecords[3]['_link']; ?>
<a href="<?php echo $mylink ?>"><img src="<?php echo $myImage['thumbUrlPath'] ?>" width="<?php echo $myImage['thumbWidth'] ?>" height="<?php echo $myImage['thumbHeight'] ?>" alt="" border="0"/></a>

__________________________________________________________

Hi Ron,

The code Jerry posted is for working with Nths uploads belonging to Nths records in a list of records, if you're FOREACHing over your list of records and want to display the Nth upload of each one, you can use $record['uploadFieldName'][4]. Personally, I like to assign an upload to a variable (like $upload) so I don't have to repeat the ['uploadFieldName'][4] part, like this:

<?php foreach( $affiliationsRecords as $affiliationsRecord ): ?>
  Title: <?php echo htmlencode($affiliationsRecord['title']) ?>

  2nd Upload:
  <?php $upload = @$affiliationsRecord['uploadFieldName'][1] ?>
  <?php if ($upload): ?>
    <img src="<?php echo $upload['thumbUrlPath'] ?>" width="<?php echo $upload['thumbWidth'] ?>" height="<?php echo $upload['thumbHeight'] ?>" />
  <?php else: ?>
    None!
  <?php endif ?>  

<?php endforeach ?>

Does that help? Please let us know if you have any questions!

Hi Chris,

Thanks for the addition, I'll add that  approach to the recipe.

Jerry Kornbluth

Thanks Chris ... that's exactly what I did.  I set a variable for the second photo in the array when I declared the viewer so I could check for it's existence later in the page and if so, create a More Photos div.  Jerry steered me to what I remember seeing ... just had a senior cerebral lapse.

Thanks again!

That's Jerry, what I needed ... couldn't remember where I saw it. 

Thanks for the post and have a wonderful weekend!