Foreach, with variation every X

Hi Rob,

Yes, there's a modulus operator that does that. http://www.php.net/manual/en/language.operators.arithmetic.php

So, $a % $b gives you the remainder of $a divided by $b. So if you have a counter you can test if it cleanly divides into 3 like this:

if (($counter % 3) == 0) { ...

Or, if the remainder of your counter divided by 3 is zero.

Or, in one line:

<?php foreach ... ?>
<?php $isThird = @++$myCounter % 3 == 0; ?>
<?php
if ($isThird) { $class = "bucket"; }
else { $class = "bucketThird"; }
?>

or

<?php if ($isThird): ?> ... <?php endif ?>

Sometimes it's easier (simpler to understand) to just have a counter and reset it when it gets to 3, but both would work:

$counter = 0;
foreach ...
$counter++;

if ($counter == 3) {
$counter = 0;
print "3rd row";
}

Let me know if one of those solutions works for you.

Hi again,

Just an update on what worked for me:

<?php $counter = 1; ?>
<?php foreach ($productsRecords as $record): ?>

<?php if ($counter <> 4): ?>
<p>Normal</p>
<?php endif ?>

<?php if ($counter == 4): ?>
<p>This is forth</p>
<?php $counter = 0; ?>
<?php endif ?>

<?php $counter++; ?>
<?php endforeach; ?>

Many thanks Dave
Rob

Glad it's working. Thanks for sharing your code! :)