Best way to use link field option

Hi Damon,
Thanks for the quick response! I have sent my details using that form now.

The support rep wasn't able to help and instead referred me to the consulting dept.

Is there anyone here who has done something similar that may be able to help out and offer some possible solutions? Any help appreciated :)

Hi Kate.

We probably should have just moved that in to consulting the first time. Would you mind emailing me FTP details and a link to this forum post through consulting@interactivetools.com

I know you've done that in the past several times but we don't hold onto that for very long. Thanks!

Let's say i have the same problematic.
I get no error but it only display ONE agent (with all its requested fields).
And something strange is that the AGENT displayed is not associated with the SALE, when i check i found that the AGENT displayed is simply the very first entry of AGENT table.

Question : how to force to display only the AGENT(s) associated with the given SALE?

Hi there.

I think what you are running into here is the ownership of the listing.

What you'll want to do is go into the program and modify a listing. Up at the top you'll see something that says, created by and then it will have a name. This is the agent that will show up when you click to see the agent details for any listing.

Make sure that name says the appropriate agent. If you are logged in as admin, you can actually change this setting so it's correct.

Let me know if that make sense. Thanks!

Please, please , please tell me that someone figured this out. I am doing the exact same thing with a real estate website that I'm working on and have come to the same problem where an agent is being displayed but its the same agent for every property. It looks as though I am missing one small detail to get this to work but I have no idea what it is. Here is my code:

<?php header('Content-type: text/html; charset=utf-8'); ?>
<?php

require_once "/home/gselect/public_html/cmsAdmin/lib/viewer_functions.php";

list($listingsRecords, $listingsMetaData) = getRecords(array(
'tableName' => 'listings',
'joinTable' => 'agents',
'where' => whereRecordNumberInUrl(1),
'limit' => '1',
));
$listingsRecord = @$listingsRecords[0]; // get first record

// show error message if no matching record is found
if (!$listingsRecord) {
header("HTTP/1.0 404 Not Found");
print "Record not found!";
exit;
}

?>




<?php foreach ($listingsRecord['agents.photo'] as $upload): ?>
<img src="<?php echo $upload['urlPath'] ?>" title="<?php echo $upload['info1'] ?>" />
<?php endforeach ?>
<br /><br />
<?php echo $listingsRecord['agents.title'] ?><br />
<?php echo $listingsRecord['agents.cell'] ?> <br />
<?php echo $listingsRecord['agents.email'] ?>